And for the 10×10 blocks, those 64 tiles of zoning need 40u of roads (1.6tiles/u), but with a 12×12 block you get 96 tiles of zoning out of only 48u of roads (2tiles/u). How's that? Well, you need to pay for the roads. But not only is it more dense, but it's also cheaper. Now, I admit that only about 4% more zoning doesn't sound that exciting. How much better? ⅔ of the area (66.66…%) instead of just 64%. (Coincidentally, that's also the maximum segment length for an axis-aligned road in CSL.) So yes, it's a block length of exactly 12 that gives the best density. That shows that the 'obvious' 10×10 grid is actually only as good as a 15×15 grid: It's hard for me to grok that quotient in my head, so let's just graph it and see what happens: (Here, and in the rest of the section, we assume a small-2u-road.)įor the general case of a square of side 𝓁, the zoneable area is (𝓁-2)²-max(0, 𝓁-10)²-the area inside the road minus the area in the middle where the zoning doesn't reach-and the total area is 𝓁². For the 10×10 grid, the calculation is simple: we get 8² zonable tiles in a 10² tile area, for a density of exactly 64%.
